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9-6/x^2=0
Domain of the equation: x^2!=0We multiply all the terms by the denominator
x^2!=0/
x^2!=√0
x!=0
x∈R
9*x^2-6=0
We add all the numbers together, and all the variables
9x^2-6=0
a = 9; b = 0; c = -6;
Δ = b2-4ac
Δ = 02-4·9·(-6)
Δ = 216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{216}=\sqrt{36*6}=\sqrt{36}*\sqrt{6}=6\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{6}}{2*9}=\frac{0-6\sqrt{6}}{18} =-\frac{6\sqrt{6}}{18} =-\frac{\sqrt{6}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{6}}{2*9}=\frac{0+6\sqrt{6}}{18} =\frac{6\sqrt{6}}{18} =\frac{\sqrt{6}}{3} $
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